Ask question

Ask question

All categories

2 years ago

13

The system with one and only one solution set is called a/an system

1 answer:

beks73 [17]2 years ago

6 0

Answer:

Consistent and Independent System

Step-by-step explanation:

A system with at least one solution is a consistent system. A consistent system is said to be independent if it has <u>exactly one solution</u> (often referred to as the <em>unique</em> solution). The graphs intersect at exactly one point, which gives an ordered-pair (x, y) as the solution of the system.

You might be interested in

Evaluate <br> 3^-3*3^4*3*3^-5

miss Akunina [59]

To multiply exponents with like bases, simply add the exponents...

3^-3 × 3^4 × 3 × 3^-5 =

add exponents across, remember just 3 means 3^1.

-3 + 4 + 1 + -5 = -3

answer is 3^-3

8 0

3 years ago

While exercising, Julie found that her heart was beating 12 times every 5 seconds. How many times was it be eating per minute?

PIT_PIT [208]

Well how many seconds are in a minute

8 0

3 years ago

Read 2 more answers

What is the approximate volume of the cone ?

lubasha [3.4K]

Answer:1206cm

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago

PLEASE ANSWER + BRAINLIEST!!!

quester [9]

Use the Cosine Rule

q^2 = 20^2 + 30^2 - 2^20*30 cos 15

= 140.89

so q = sqrt 140.89 = 11.9 (answer)

6 0

3 years ago