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3 years ago

Determine the absolute value of -11. A) -11 B) 0 C) ±11 D) 11

Mathematics

2 answers:

Svetlanka [38]3 years ago

8 0

Answer:

D. 11.

Step-by-step explanation:

We write the absolute value of a number by placing it in vertical lines: |-11|.

The absolute value = |-11| = 11 (it is always the positive value of the item in the vertical lines).

Leviafan [203]3 years ago

7 0

Answer: D) 11

Step-by-step explanation:

Absolute value is really simple to remember. Anything to do with absolute value will always be positive. The absolute value of -11 is positive 11.

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What is the volume of a right circular cylinder with a radius of 5 cm and a height of 12 cm?

dexar [7]

Answer:

Answer C

Step-by-step explanation:

Formula

Volume = pi * r^2 * h

Givens

r = 5 cm
h = 12 cm

Solution

V = pi * 5^2 * 12
V = pi * 25 * 12
V = 300 pi

Answer = C

8 0

3 years ago

A circle is centered at the point (-7, -1) and passes through the point (8, 7).The radius of the circle is____ units. The point

denis-greek [22]

Answer:

Part 1) The radius of the circle is r=17 units

Part 2) The points (-15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(-7, -1) and (8, 7)

substitute

$r=\sqrt{(7+1)^{2}+(8+7)^{2}}$

$r=\sqrt{(8)^{2}+(15)^{2}}$

$r=\sqrt{289}$

$r=17\ units$

step 2

Find out the y-coordinate of point (-15,y)

The equation of the circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

substitute the values

$(x+7)^2+(y+1)^2=17^2$

$(x+7)^2+(y+1)^2=289$

Substitute the value of x=-15 in the equation

$(-15+7)^2+(y+1)^2=289$

$64+(y+1)^2=289$

$(y+1)^2=289-64$

$(y+1)^2=225$

square root both sides

$(y+1)=(+/-)15$

$y=-1(+/-)15$

$y=-1(+)15=14$

$y=-1(-)15=-16$

therefore

we have two solutions

point (-15,14) and point (-15,-16)

see the attached figure to better understand the problem

8 0

3 years ago

Hey I need help with this question:<br><br> 6(x-3)^2-26 = 10

ra1l [238]

Answer:

x = 3 ±sqrt(6)

Step-by-step explanation:

6(x-3)^2-26 = 10

Add 26 to each side

6(x-3)^2-26+26 = 10+26

6(x-3)^2 = 36

Divide by 6

6/6(x-3)^2 = 36/6

(x-3)^2 = 6

Take the square root of each side

sqrt((x-3)^2) = ±sqrt(6)

x-3 = ±sqrt(6)

Add 3 to each side

x-3+3 =3 ±sqrt(6)

x = 3 ±sqrt(6)

7 0

3 years ago

Find the domain and range of this relation? (Assume there are arrows at both ends of the relation.)

Radda [10]

Answer:

Domain: ( -∞ , ∞ )
Range: ( -∞ , 4 ]

Step-by-step explanation:

Hi there!

The domain tells us the possible x-values of a function. Because there are arrows at the end of each side, it means the graph is travelling infinitely to both the left and the right side. This means the the domain is all real numbers, meaning that for any value of x, there is a real value for y.

( -∞ , ∞ )

The range tells us the possible y-values of a function. Both sides of the graph are travelling infinitely downwards, starting from 4.

( -∞ , 4 ]

I hope this helps!

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2 years ago

Jamal hiked on two trails. The first trail was 3 1/3 miles long, and the second trail was 1 3/5 times as long as the first trail

monitta

The answer is 6.6 repeating, so 6.6666...

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3 years ago