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andrezito [222]
3 years ago
12

Find the greatest common factor 35a^7b^4c^2 and -7a^3bc^2d​

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

35742

Step-by-step explanation:

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A pumpkin is thrown horizontally off of a building at a speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fract
4vir4ik [10]

Answer:−47.0

​

​

Step-by-step explanation:Step 1. List horizontal (xxx) and vertical (yyy) variables

xxx-direction yyy-direction

t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text

a_x=0a

x

​

=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a

y

​

=−9.8

s

2

m

​

a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction

\Delta x=12\,\text mΔx=12mdelta, x, equals, 12, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text

v_x=v_{0x}v

x

​

=v

0x

​

v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=\text ?v

y

​

=?v, start subscript, y, end subscript, equals, start text, question mark, end text

v_{0x}=2.5\,\dfrac{\text m}{\text s}v

0x

​

=2.5

s

m

​

v, start subscript, 0, x, end subscript, equals, 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v

0y

​

=0v, start subscript, 0, y, end subscript, equals, 0

Note that there is no horizontal acceleration, and the time is the same for the xxx- and yyy-directions.

Also, the pumpkin has no initial vertical velocity.

Our yyy-direction variable list has too many unknowns to solve for v_yv

y

​

v, start subscript, y, end subscript directly. Since both the yyy and xxx directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:

\Delta x=v_xtΔx=v

x

​

tdelta, x, equals, v, start subscript, x, end subscript, t

Once we know ttt, we can solve for v_yv

y

​

v, start subscript, y, end subscript using the kinematic equation that does not include the unknown variable \Delta yΔydelta, y:

v_y=v_{0y}+a_ytv

y

​

=v

0y

​

+a

y

​

tv, start subscript, y, end subscript, equals, v, start subscript, 0, y, end subscript, plus, a, start subscript, y, end subscript, t

Hint #22 / 4

Step 2. Find ttt from horizontal variables

\begin{aligned}\Delta x&=v_{0x}t \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ &=\dfrac{12\,\text m}{2.5\,\dfrac{\text m}{\text s}} \\\\ &=4.8\,\text s \end{aligned}

Δx

t

​

 

=v

0x

​

t

=

v

0x

​

Δx

​

=

2.5

s

m

​

12m

​

=4.8s

​

Hint #33 / 4

Step 3. Find v_yv

y

​

v, start subscript, y, end subscript using ttt

Using ttt to solve for v_yv

y

​

v, start subscript, y, end subscript gives:

\begin{aligned}v_y&=v_{0y}+a_yt \\\\ &=\cancel{0\,\dfrac{\text m}{\text s}}+\left(-9.8\,\dfrac{\text m}{\text s}\right)(4.8\,\text s) \\\\ &=-47.0\,\dfrac{\text m}{\text s} \end{aligned}

v

y

​

​

 

=v

0y

​

+a

y

​

t

=

0

s

m

​

​

+(−9.8

s

m​

)(4.8s)

=−47.0

s

m

5 0
2 years ago
Read 2 more answers
Given points A – 2,1) and B(4,5), find the coordinates of point P along the directed line
Sav [38]
Yea I have no proof to do that much cause
4 0
2 years ago
Dianna is grading a students project the students project score is 80 but the student earned 5% bonus of the project score by do
malfutka [58]

Answer:

84

Step-by-step explanation:

80 + (80 * 5/100) = 84

simply take the 5% of 80 which is 4 and add it back to 80 which is 84

6 0
3 years ago
Between the time Iko woke up and lunchtime, tue temperature rose by 11 degrees. Then by the time he went to bed, the temperature
Ierofanga [76]

Answer:

T_b=(x-3)\textdegree

Step-by-step explanation:

let x° be temperature when he woke up. Given that the temperature rose  by 11° then later dropped by 14°. Also let T_b be temperature at time she went to bed.

-We add the temperature rise and subtract the temperature drop to find temperature at time she goes to bed.

-The temperature relative to time of waking up can be expressed as:

T_b=x\textdegree\pm\bigtriangleup T\textdegree\\\\T_b=x\textdegree+11\textdegree-14\textdegree\\\\T_b=(x-3)\textdegree

Hence, the temperature relative to the time Iko woke up is (x-3)°

4 0
2 years ago
Kelly answered 3 items on a test incorrectly, this was 6% of her test. How many questions were on her test? Plz, help me ASAP...
ExtremeBDS [4]

50 and this is a filler


6 0
3 years ago
Read 2 more answers
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