2 years ago

PLEASE HELP WITH QUESTION...use graphs and tables to find the limit and identify any vertical asymptotes

Mathematics

1 answer:

djyliett [7]2 years ago

8 0

Answer:

Step-by-step explanation:

First, you do the standard algorithm, then you have to slove, your answer is 120

You might be interested in

Help I don't get it and I need it done fast.take your time if your going to help.

Zigmanuir [339]

Answer:

Step-by-step explanation:

4 0

2 years ago

What is 2.o85 x 10*6 in standard dorm

RSB [31]

The answer to the question is 2,085,000

8 0

2 years ago

a crane lifts a 450 kg concrete to the top of a 50 m building in 5 s. assuming g=10 m/s² calculate a) the potential energy of th

Juliette [100K]

Answer:

Step-by-step explanation:

The work done changes the potential energy

ΔPE = mgΔh = 450(10)(50) = 225,000 = 225 kJ

power is the rate of doing work

P = 225000/5 = 45000 W = 45 kW

5 0

2 years ago

In which quadrant or axis is the point (-1, 2) located?

zheka24 [161]

The point (-1,2) is in quadrant 2

5 0

3 years ago

Read 2 more answers

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

2 years ago

Read 2 more answers

PLEASE HELP WITH QUESTION...use graphs and tables to find the limit and identify any vertical asymptotes ​

PLEASE HELP WITH QUESTION...use graphs and tables to find the limit and identify any vertical asymptotes