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3 years ago

9

Which equation is equivalent to Sq rt x+ 11 = 15?

1 answer:

vladimir2022 [97]3 years ago

7 0

I do y get this but it might be 4

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Pls help… grade 6/ primary 6 work. thanks!

Yuri [45]

Answer:

320

Step-by-step explanation:

go backwards, 75 + 45 = 120

120 * 5/3 = 200

200+40 = 240

240 *4/3 = 320

3 0

2 years ago

Solve the system of linear equations y= 2x -3Y= x + 6

Alja [10]

Answer:

x=9, y=15. (9, 15).

Step-by-step explanation:

y=2x-3

y=x+6

----------

2x-3=x+6

2x-x-3=6

x-3=6

x=6+3

x=9

y=9+6=15

7 0

2 years ago

If the side length of a square is 4 inches, its area is __ square inches and its priemeter is __ inches.

Grace [21]

Answer:

16 for both

Step-by-step explanation:

4 0

3 years ago

There are 4 grams of sugar in 1⁄2 of a liter of a new sports drink. How much sugar is in 3⁄4 of a liter of the sports drink?

Ira Lisetskai [31]

The correct answer is 6 grams of sugar

Hope this helped :)

4 0

4 years ago

given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a ration

Vedmedyk [2.9K]

Answer:

$\tan(A) = \frac{3}{5}$

Step-by-step explanation:

Given

$\sin(A) = \frac{3}{\sqrt {34}}$

$0 \le A \le 90$ --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

$\tan(A) = \frac{Opposite}{Hypotenuse}$

and

$\sin(A) = \frac{3}{\sqrt {34}}$

By comparison:

$Opposite = 3$

$Hypotenuse = \sqrt{34$

So, the Adjacent is:

$Hypotenuse^2 = Adjacent^2 + Opposite^2$

$(\sqrt{34})^2 = Adjacent^2 + 3^2$

$34 = Adjacent^2 + 9$

Collect like terms

$Adjacent^2 =34 - 9$

$Adjacent^2 =25$

Take square roots

$Adjacent =\sqrt{25$

$Adjacent =5$

The tangent of an angle is:

$\tan(A) = \frac{Opposite}{Adjacent}$

This gives:

$\tan(A) = \frac{3}{5}$

8 0

3 years ago