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4 years ago

If 75% of a number is 60, what is 20% of the number

Mathematics

2 answers:

Colt1911 [192]4 years ago

6 0

I hope this is right i think the answer is 40

Elan Coil [88]4 years ago

3 0

I think it is 16 how i got that is by finding the number that 60 was 75% of which is 80 then i took 80 * 20 / 100 to get 16 which should 20 precent of 80 hope that helps

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Evaluate the following integral or state that it diverges. <br><br> *integral 0 to 1 (ln x)do

dolphi86 [110]

Answer:

-1

Step-by-step explanation:

so firstly we solve by integrating by parts.

lnX × X - the integral of x/x

so the integral is Xln(X) - X

so the value should converge at -1

6 0

2 years ago

Can someone help please asap

ch4aika [34]

Sn = (a1) x (1 - r^n) / (1 - r)

Substituting the known values:

S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9

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3 years ago

Whats the answer to this question<br> Please give me the right answer to this question

vichka [17]

Slope is 7 root 2 I hope this

7 0

3 years ago

Read 2 more answers

Leila puts an integer into the "In" box of each machine.

kykrilka [37]

The machines represent equivalent expressions.

The output produced by both machines is 372

The equation represented on machine A is:

$\mathbf{y = 2(5x + 3) - 24}$

The equation represented on machine B is:

$\mathbf{y = 4(2(x + 11) - 7)}$

Where: x and y represent the inputs and the outputs, respectively

When the outputs are the same, it means:

$\mathbf{y = y}$

So, we have:

$\mathbf{2(5x + 3) - 24 = 4(2(x + 11) - 7)}$

Open brackets

$\mathbf{10x + 6 - 24 = 8x + 88 - 28}$

$\mathbf{10x - 18 = 8x + 60}$

Collect like terms

$\mathbf{10x - 8x = 18 + 60}$

$\mathbf{2x = 78 }$

Divide both sides by 2

$\mathbf{x = 39 }$

Substitute 39 for x in $\mathbf{y = 2(5x + 3) - 24}$

$\mathbf{y = 2 \times (5 \times 39 + 3) - 24}$

$\mathbf{y = 372}$

Hence, the output produced by both machines is 372

Read more about equivalent expressions at:

brainly.com/question/15715866

4 0

3 years ago

What is the completely factored form of f(x)=x^3-7x^2+2x+4

xxMikexx [17]

$Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)$

$Steps:$

$x^3-7x^2+2x+4$

$Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}$

$\frac{x^3-7x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}$

$\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}$

$\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4$

$\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

8 0

3 years ago