Can someone help and explain for me please

ABC with verticles A(1,2) B(3,1) C(3,4) translated 2 units left and 1 unit up

GenaCL600 [577]

A' : -1, 3
B': 1, 2
C': 1, 5

3 0

3 years ago

055

Citrus2011 [14]

B. 855/4.5 is 190. Out of all four choices, 475 cal / 2.5 servings is the only which leave you 190.

4 0

3 years ago

Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr

Fed [463]

Answer:

There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

Given

Let subscript 1 represent men and 2 represent women, respectively.

$n_1 = 25$

$n_2 = 21$

$s_1 = 0.98$

$s_2 = 1.02$

$\alpha = 0.02$

Required

Determine if here is enough evidence

First, we need to state the hypotheses

$H_o: \sigma_1^2 = \sigma_2^2$

$H_1: \sigma_1^2 \ne \sigma_2^2$

Next, calculate the test statistic using:

$F = \frac{s_1^2}{s_2^2}$

$F = \frac{0.98^2}{1.02^2}$

$F = 0.923$

Calculate the rejection region;

But first, calculate the degrees of freedom

$df_1 =n_1 - 1$

$df_1 =25 - 1$

$df_1 =24$

$df_2 = n_2 -1$

$df_2 = 21 - 1$

$df_2 = 20$

Using the F Distribution: table

$c = \frac{\alpha}{2}$

$c = \frac{0.02}{2}$

$c = 0.01$

At 0.01 level (check row 20 and column 24), the critical value is:

$f_{0.01,24,20} = 2.86$ --- the upper bound

At 0.01 level (check row 24 and column 20), the critical value is:

$f_{0.01,20,24} = 2.74$

Calculate the inverse F distribution.

$f_{0.99,20,24} = \frac{1}{f_{0.01,20,24}} = \frac{1}{2.74} =0.365$ ---- the lower bound

The rejection region is then represented as:

$0.365 < Test\ Statistic < 2.86$

If the test statistic falls within this region, then the null hypothesis is rejected

$F = 0.923$ --- Test Statistic

$0.365 < 0.923 < 2.86$

The above inequality is true; so, the null hypothesis is rejected.

This implies that, there is no sufficient evidence.

7 0

3 years ago

The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.

sineoko [7]

Answer=12.6

QR=9
QP=6
TU=19
TS=?

The triangles are similar, so the following equation can be made

9 6
____=____
19 x

Cross multiply
9x=114
divide both sides by 9
x=12.6 (with the 6 repeating) or 12 2/3

TS=12.6

3 0

3 years ago

Read 2 more answers

Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°

jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1, ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3 and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

=540°=180°

=360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0

3 years ago