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4 years ago

Help wit this chemistry question and how do you do it ?

Chemistry

1 answer:

Alex4 years ago

7 0

The number of protons and neutrons can be found on your periodic table or looked up on the internet. the number of electrons must be determined by looking at the charge and determining how many would be needed.

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Identify each definition that applies to the compound in red. Check all that apply. F-+HSO4-=>HF+SO4^2-

viva [34]

Answer:Bronsted lowry base (if red term is F-)

Explanation:

just did on edge

5 0

3 years ago

MASTERING CONCEPTS<br> 31. List three examples of substances. Explain why each<br> is a substance.

SOVA2 [1]

Answer:

Explanation:

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6 0

3 years ago

a 0.555 g sample of mayonnase was burned in excess oxygen inside a bomb calorimeter with a total heat capacity (bomb and water)

Fofino [41]

Answer:

$Dietary\ Calories=65.6kcal$

Explanation:

Hello!

In this case, since we can see that the heat released by the combustion of the mayonnaise is absorbed by the bomb calorimeter and water, we can set up the following equation:

$m_{mayonnaise}q_{mayonnaise}=C\Delta T$

Whereas q for mayonnaise stands for the heat due to its usage; thus, we plug in to obtain:

$q_{mayonnaise}=\frac{5.20kJ/\°C*2.93\°C}{0.555g} \\\\q_{mayonnaise}=27.45\frac{kJ}{g}$

Now, if 10.0 g are eaten, the energy provided by it turns out:

$E_{mayonnaise}=27.45kJ/g*10.0g\\\\E_{mayonnaise}=274.5kJ$

And we need that value in dietary calories, 1 kcal:

$Dietary\ Calories=274.52kJ*\frac{1kcal}{4.184kJ}\\\\ Dietary\ Calories=65.6kcal$

Best regards!

4 0

3 years ago

Hello

nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver = $\frac{x}{108 g/mol}$

Number of atoms = $Moles\times N_A$

Where : $N_A$ = Avogadro number

Moles of gold = $\frac{0.1x}{197 g/mol}$

Silver atoms = $\frac{x}{108 g/mol}\times N_A$

Gold atoms = $\frac{0.1x}{197 g/mol}\times N_A$

The ratio of the number of atoms of gold and silver in the ornament:

$=\frac{\frac{0.1x}{197 g/mol}\times N_A}{\frac{x}{108 g/mol}\times N_A}$

= 197 : 1080

3 0

3 years ago

Write the balanced equation for the reaction between HCl and NaOH. Then, calculate the molarity of the NaOH.

andre [41]

Answer:

HCl (aq) + NaOH (aq) --> H2O (L) + NaCl (aq)

Explanation:

HCl is a strong acid while NaOH is a strong alkali. Hence both should dissociate completely in water and 1 mol of HCl will fully neutralise 1 mol of NaOH.

I'm assuming that Part 2 on molarity is part of a data based question that requires you to calculate the number of moles of NaOH based on the data provided and the equation that you are required to balance. Hence, I can't help you with it as I do not have the values.

5 0

3 years ago