MASTERING CONCEPTS 31. List three examples of substances. Explain why each is a substance.
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<u>Answer:</u>
<u>Balancin</u>g is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient and the subscript
For example contains
5 × 1 = 5,Ca atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example we multiply coefficient
subscript
number outside the bracket.......... to find the number of atoms
(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So
3 × 3 = 9, Ca atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
So
Let us balance the equation given
(Unbalanced)
Reactant side - Number of atoms of each element - Product side
1 - Sb - 1
2 - Cl - 3
So we have on the product side odd number of Cl to convert to even number, multiply by 2
The equation changes to
Reactant side - Number of atoms of each element - Product side
1 - Sb - 2
2 - Cl - 6
Multiplying Sb by 2 and
The equation is balanced now!!!!
Reactant side - Number of atoms of each element - Product side
2 - Sb - 2
6 - Cl - 6
Balanced.