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Jlenok [28]
2 years ago
11

MASTERING CONCEPTS 31. List three examples of substances. Explain why each is a substance.

Chemistry
1 answer:
SOVA2 [1]2 years ago
6 0

Answer:

vc

Explanation:

cvcv

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points

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Why this process is called a cycle
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<span>because it is a pattern; airgo cycle</span>
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HELP PLEASE I WILL MARK YOU AS A BRAINLIEST
never [62]

Answer:

a food pyramid.

Explanation:

the food pyramid shows how autotrophs are at the bottom and how the top predators are at the top, in this case the eagle.

8 0
3 years ago
Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
a patient is to receive 25 mg of methimazole, a drug used to treat hyperthyroid conditions. the drug is dissolved in solution co
Rainbow [258]
The drug has a concentration of 6 mg per 1 ml. Therefore, to know that number of ml containing 25 grams, we will simply do cross multiplication as follows:
amount of drug = (25 x 1) / 6 = 4.1667 ml

Therefore, for the patient to receive 25 mg of methimazole, he/she should take 4.1667 ml of the drug solution.
8 0
2 years ago
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