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2 years ago

A bicycle pump contains 250 mL of air at a pressure of 102 kPa. If the pump is

Chemistry

1 answer:

CaHeK987 [17]2 years ago

3 0

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

<h3>Boyle's law</h3>

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

P1= 102 kPa= 10335.1 atm (being 1 kPa= 101.325 atm)
V1= 250 mL
P2= 2.25 atm
V2= ?

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

Learn more about Boyle's law:

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Answer:

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3 years ago

A sample of an unknown gas with a mass of 8.21 g has a volume of 4.8064 L when the temperature is 200oC and the pressure is 1.81

Pie

Answer:

The answer to your question is M = 36.49 g

Explanation:

Data

mass = 8.21 g

volume = 4.8064 L

Temperature = 200°C

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M = ?

Process

1.- Convert temperature to °K

°K = 273 + 200

°K = 473

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