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enyata [817]
3 years ago
10

Find the point below that lies on the line y-7=4(x-2)

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

Step-by-step explanation:

y-7=4(x-2)

we need to simplify the y to het a

y-7=4x-8 (i did 4x-8 because of 4(x-2)

now y= 4x-8+(-7)

after calculating -8+(-7) IT becomes

y=4x-15

okay we have the guide Line

y=4x-15

the a is 4

because

a = {y=a.x+b}

now we need to find the points using this guide Line

y=4x-15

x= 2(you can add any number here ,we Just need to know where the point is )

y= 4(2)-15

y=8-15

y= -7

points are (2,7)

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Usimov [2.4K]

Answer:

1,3,4,5,6,10,11,14,16,17,18,20

Step-by-step explanation:

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Y= x + 1<br>y= -x + 5 <br><br>what's the answer pls I need it asap​
Lena [83]

Answer:

X= 2 and y = 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How long will it take to have R30 000 for a trip to Europe if I invest R20 000 now at 15% per year, compounded quarterly?
maw [93]

<span>Compound  interest  formula</span>

A=P(1+ \frac{r}{n} )^{nt}

 

Where

<span>
A= Future value
P = the Principal (the initial amount of money) 
r = annual interest rate</span>

t = time

<span>n= number of times compounded in one t






Remark
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r is generally a percentage like 3%, 7% etc and are applied in the formula as 0.03, 0.07..., 

the interest is compounded generally annually (n=1), quarterly (n=4), monthly (n=12), etc...

t is in years,


In our problem:

</span>

A= 30 000

P =20 000

r = 15%=0.15

time = t = ?

n= 4

applying the formula:

A=P(1+ \frac{r}{n} )^{nt}\\\\30,000=20,000(1+ \frac{0.15}{4} )^{4t}\\\\ \displaystyle{\frac{30,000}{20,000} =(1.0375)^{4t}

\displaystyle{ 1.5={(1.0375^4)}^t\\\\

1.5=1.159^t\\\\ \displaystyle { t=log_{1.159}1.5=2.75

75% of 12 months is 3/4 of 12 months, which is 9 months

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3 0
3 years ago
What is x and y math help
Readme [11.4K]
<h3>Answer:</h3>
  • 20 cans of cola
  • 10 cans of root beer
<h3>Step-by-step explanation:</h3>

x and y are whatever you want them to be.

It can be convenient for solving a problem like this to use x and y to represent <em>what the problem is asking for</em>: the number of cans of cola and the number of cans of root beer. It is also convenient (less confusing) to use those variable names in the same order that the nouns of the problem are named:

... x = # of cans of cola

... y = # of cans of root beer

Then the problem statement tells you ...

... x + y = 30 . . . . . . . 30 cans total were bought

... x = 2y . . . . . . . . . . the number of cans of cola is twice the number of cans of root beer

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This set of equations is nicely solved by substitution: use the second equation to substitute for x in the first.

... (2y) +y = 30 . . . . . put 2y where x was

... 3y = 30 . . . . . . . . collect terms

... y = 10 . . . . . . . . . divide by 3

... 2y = x = 20

<em>You're not done yet. You need to answer the question the problem asks.</em>

Jared bought 20 cans of cola and 10 cans of root beer.

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<em>Comment on x and y</em>

You customarily see x and y as the variables of a problem. Personally, I like to use variables that remind me what they stand for. In this problem, I might use "c" for cans of cola and "r" for cans of root beer. Then when I've found the solution, I know exactly how it relates to what the question is asking.

Always start by writing down what the variables stand for (as we did here). Sometimes, this is called <em>writing a Let statement</em>: <u>Let</u> x = number of colas; <u>let</u> y = number of root beers.

<em>Comment on problems of this type</em>

When a proportional relationship is given between the items in a sum (2 cola cans for every root beer can), it is often convenient to work the problem in terms of groups of items. Here, a group of 3 items can consist of 2 cola cans and 1 root beer can. Then 30 items will be 10 groups, so 10 root beers and 20 colas. The problem is solved even before you can name the variables.

Even when the relationship isn't exactly proportional, you can add or subtract the extras and still work the problem this way. Had we said colas numbered 3 more than twice as many root beers, we could have our groups of 3 total 27 (30 less the 3 extra), giving 9 root beers and 21 colas (3 + 2·9).

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A person sold 100 shares of a stock at a loss of 40%. If the selling price for the 100 shares was $3,000, which of the following
Kisachek [45]

A person sold 100 shares of a stock at a loss of 40%.

selling price for the 100 shares was $3,000

Let the stock was bought at $x then we can write

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Hence Amount paid for the Stock was $5000

7 0
3 years ago
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