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Kipish [7]
2 years ago
14

Someone buys 6 cakes for 8$ each he sells them for ten each then he got 8 more and selled them for 10$ how much money does he ha

ve left???
Mathematics
1 answer:
trapecia [35]2 years ago
4 0

Answer: $28

Step-by-step explanation:

The person bought 6 cakes for $8 which reduces his money by:

= 6 * 8

= -$48

He then sells them for $10 each so the money made was:

= 10 * 6

= $60

He then buys 8 more for the same price which will reduce his money by:

= 8 * 8

= -$64

He sells these 8 for $10 so the money made was:

= 8 * 10

= $80

Total money left is therefore:

= 60 + 80 - 48 - 64

= $28

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Solve for e 9e + 4 = − 5e + 14 + 13e 9e + 4 = -5e + 14 + 13e
Rasek [7]

Answer: e= -5

                   ----

                     4




5 0
3 years ago
Read 2 more answers
Help fast plz I WILL DO ANYTHING
kaheart [24]

Answer:

I only have 2

Step-by-step explanation:

each sides is multiplying by 2

each order is multiplying by 12

5 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
3 years ago
(Would be very much appreciated if it was answered asap, please and thank you! =D)
LUCKY_DIMON [66]
The equation 3.3x - 6.6 = 2.7x is equal to the expression 0.6x = 6.6 (2nd option)
4 0
3 years ago
Paul is decorating cupcakes. He can decorate 3/4 of a cupcake per minute. At this rate, how many cupcakes can he decorate in 12
Ivenika [448]

Answer:

3/4 x 12/1 because if you can decorate 3/4 a cupcake per minute, you multiply 3/4 by 12 to find the total amount of cupcakes he could decorate. 3/4 x 12/1 = 9 Paul can decorate 9 cupcakes in 12 minutes.

Step-by-step explanation:

hope tis helps im not good at match but i know this

7 0
2 years ago
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