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3 years ago

Which point is an x-intercept of the quadratic function f(x) = (x – 4)(x + 2)?

2 answers:

7 0

The quadratic equation is in factored form, which is f(x) = (x - a)(x - b), where a and b are the x-values for the x-intercepts.

The x-values for the x-intercepts are 4 and -2. We know that the y-value at any x-intercept must be 0 (otherwise it isn't an x-intercept).

Thus, either the points (4,0) or (-2,0) must be your answer (the question is only asking for one x-intercept).

mr Goodwill [35]3 years ago

6 0

Answer:

(-2,0)

Step-by-step explanation:

You might be interested in

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC. Then list the s

Allisa [31]

For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14

For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1

So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.

5 0

3 years ago

The sum of two numbers is 30.the first number is 1/5 of the second number. what are the numbers?

gizmo_the_mogwai [7]

The 2md number can be y. This makes the first number 1/5 of y

Your equation is y + 1/5y = 30
You can randomly plug in numbers and you get that the first number is 5. This means that the second number is 25

6 0

3 years ago

Given f (x) = 3x +4, find f (2). A 6 B) 7 C 10 D) 14.

Tom [10]

Answer:

F(2)= 10 or C

Step-by-step explanation:

You just need to plug the answers in.

F(x)=3x+4

f(2)=3(2)+4

f(2)=6+4

f(2)= 10

7 0

3 years ago

Find the area of the figure. Sides meet at right angles. No links please.

ss7ja [257]

Answer:

40 ft²

Step-by-step explanation:

Divide the figure into 2 rectangles and find their areas.

The area of the smaller rectangle

= 3 × 4

= 12 ft²

The area of the larger rectangle

= (8-4) × 7

= 28 ft²

The area of the figure

= 12 + 28

= 40 ft²

4 0

2 years ago