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nlexa [21]
3 years ago
10

Look at the image if you need me to add the answers so you can see them better i will

Physics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

0.75 meters per second; north

Explanation:

speed (velocity)= distance/time

15 meters= distance

20 seconds= time

15/20= 0.75 meters per second; north

Hope this helps!

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When a car maintains a velocity of exactly 65 mph, what is it's acceleration​
Readme [11.4K]

When a car maintains a velocity of exactly 65 mph, it's acceleration​ is zero.

<h3>What is acceleration?</h3>

The acceleration is time rate of change of velocity.

When the velocity is not changing with respect to time, it is said to be an object moving with constant velocity.

At constant velocity, there is no acceleration.

Thus, when a car maintains a velocity of exactly 65 mph, it's acceleration​ is zero.

Learn more about acceleration.

brainly.com/question/12550364

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4 0
3 years ago
Read 2 more answers
Explain what makes rhombus different from other quadrilaterals
navik [9.2K]

The critical difference is the fact that all four sides of a rhombus have
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There are several other distinguishing characteristics, but if you make the
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6 0
3 years ago
What force was applied to an object if 35 J of work was done and the object moved 7 m? Show your work.
ahrayia [7]

Answer:

5 N

Explanation:

The work done by a force on an object is (assuming that the direction of the force is parallel to the displacement of the object):

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem, we know that:

W = 35 J is the work done

d = 7 m is the displacement of the object

Therefore, we can re-arrange the equation to calculate the force applied:

F=\frac{W}{d}=\frac{35 J}{7 m}=5 N

8 0
3 years ago
Cardiovascular fitness measures the health of which body system?
Aloiza [94]

Answer:

I believe it is the circulatory system.

Explanation:

Have a nice day.

5 0
3 years ago
An object is placed at 4cm distance in front of a concave mirror of radius of curvature 24cm.find the position of image.is the i
n200080 [17]
Radius of curvature, r = 2f

24 cm = 2f

2f = 24 

f = 24/2 = 12

Hence the focal length is = 12 cm.

Object distance, u = 4 cm.

Since the object is placed between the focus and the pole of the mirror, at this position for a concave mirror, the resulting image would be virtual and would be behind the mirror.

1/u - 1/v = 1/f

1/4 - 1/v = 1/12

1/4 - 1/12 = 1/v

1/v = 1/4 - 1/12 =   (3 - 1)/12 = 2/12 = 1/6

1/v = 1/6

v = 6

Therefore the image is 6cm behind the mirror. 

Magnification = v/u = 6/4 = 3/2 = 1.5

Yes, the image is magnified by 1.5 times.

Simply copy the diagram for an object placed between the focus and the pole of a mirror from your textbook.   
6 0
3 years ago
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