Answer:
<h2>
38,769.23 miles</h2>
Explanation:
given:
A car is traveling at an average speed of 70 m/s.
find:
How many km would the car travel in 6.5 hrs. ?
solution:
distance = velocity over time
let velocity = 70 m/s
time = 6.5 hrs.
convert velocity 70 m/s into m/h for consistency of units.
<u>70 mi. </u> x <u>3600 sec.</u> = 252,000 mi/hour
sec. 1 hr.
now plugin values into the formula d = v/t
d = <u>252,000 miles/hour </u>
6.5 hours
d = 38,769.23 miles
therefore, the distance travelled in 6.5 hours with a speed of 70 m/s is 38,769.23 miles
Hi there!
(a)
Recall that:

W = Work (J)
F = Force (N)
d = Displacement (m)
Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

To the nearest multiple of ten:

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.
Thus:

(c)
Similarly, the normal force is perpendicular to the displacement, so:

(d)
Recall that the force of kinetic friction is given by:

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:

In multiples of ten:

(e)
Simply add up the above values of work to find the net work.

Nearest multiple of ten:

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)



Nearest multiple of ten:

Answer:
80×5×10=4000J
so therefore, work done on the body is 4000J
Answer:
answer is 3.05v
Explanation:
hope it is helpful and briliant
Well, Air resistance is a special type of friction (you cannot classify it in other categories). That force of air-resistance is often observed to oppose the motion of the object,( like every other frictional forces)
Hope this helps!