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AleksAgata [21]
2 years ago
5

Two coils, held in fixed positions, have a mutual inductance of M = 0.0034 H. The current in the first coil is I(t) = I0sin(ωt),

where I0 = 5.4 A, ω = 143 rad/s. Randomized Variables M = 0.0034 H I0 = 5.4 A ω = 143 rad/s show answer No Attempt 25% Part (a) Express the magnitude of the induced emf in the second coil, ε2, in terms of M and I.
Physics
1 answer:
tiny-mole [99]2 years ago
3 0

Answer:

ε₂ =2.63 V

Explanation:

given,

M = 0.0034 H

I (t) = I₀ sin (ωt)

I (t) = 5.4 sin (143 t)

\dfrac{d i(t)}{dt} = \dfrac{d}{dt}(5.4 sin (143 t))

\dfrac{d i(t)}{dt} =143 \times 5.4 cos (143 t)

magnitude of the induced emf in the second coil

ε₂ =M\dfrac{di}{dt}

ε₂ =0.0034\times 143 \times 5.4 cos (143 t)

for maximum emf

cos (143 t) = 1

ε₂ =0.0034\times 143 \times 5.4

ε₂ =2.63 V

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