To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.
Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.
Part A) Conservation of the energy
Part B) Kinematic equation of linear motion,
Here
v= 0 Because at 1.5m reaches highest point, so v=0
Therefore the velocity after the collision with the floor is 3.7m/s
PART C) Total change of impulse is given as,
inferior is an antonym of superior. Superior is an antonym of inferior.
As adjectives the difference between inferior and superior is that inferior is of lower quality while superior is higher in quality.
As nouns the difference between inferior and superior is that inferior is a person of lower stature to another while superior is a person of higher rank or quality.
The x-component of Anne's path:
80 x cos(33)
= 67.1 meters
y-component of Anne's path:
80 x sin(33)
= 43.6 meters
To draw he diagram, you draw a horizontal line starting at point 1 to the right representing 67.1 meters. At the end of this line, draw a vertical line upwards representing 43.6 meters.
Connect the start of the horizontal line at point 1 to the end of the vertical line with an angle of 33° between them.
We are given with a velocity-distance-time kinematic problem given the different times of two runners and is asked for the difference in distances the runner has ran in the track. we use the formula v= d/t where d is the distance of running, t is time and v is the velocity of the runner.
First runner,
v = d/t = 1000 m / (120+28.13s ) = 6.750826976 m/s
Second runner
Using the same velocity we determine d2.
v = d2/t2 = d2 / (120+28.48s) = 6.750826976 m/s ; d2 = 1002.362789
distance of running track is the difference of the two distance achieved by the runners, delta d= d2 - d = 2.362789 m
Answer:
The change from the liquid state to the solid state is called freezing. As the liquid cools, it loses thermal energy. ... For example, solid water melts at 0°C and liquid water freezes at 0°C. During freezing, the temperature of a substance remains constant while the particles in the liquid form a crystalline solid.
