3 years ago

The table shows the last holiday destination of 60 people.

1 answer:

6 0

Answer:

Step-by-step explanation:

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Answer: B

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3 years ago

andrezito [222]

I am writing answers directly.

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3 years ago

borishaifa [10]

Plz mark me as brainliest if this helped :)

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3 years ago

nirvana33 [79]

We have been given gross domestic product (in billions of dollars) can be approximated by $P(t)=564+t(36t^{0.6}-101)$ .

(a) In this part, we need to compute the derivative of this function:

$P'(t)=\frac{d}{dt}(564+t(36t^{0.6}-103))\\P'(t)=\frac{d}{dt}(564)+\frac{d}{dt}(t(36t^{0.6}-103))\\P'(t)=0+57.6t^{0.6}-103\\$

$P'(t)=57.6t^{0.6}-103$

(b) In this part, we need to find the value of P'(45). So, we will substitute t=45

$P'(45)=57.6(45)^{0.6}-103\\P'(45)=565.3924-103\\P'(45)=462.39$ Billion dollars per year.

(c) P'(45)=462.39 represents that 45 years after 1960, that is, in 2005, the GCP was changing at a rate of 462.39 billion dollars per year.

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3 years ago

gogolik [260]

Answer:

$89.92 \div 25 = 3.5968 \times 100 = 359.68$

therefore the answer is 359.68$

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3 years ago