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3 years ago

Math 7. Grade 7 Evaluate: 6(p÷x) - 2x , if p = 6 and x = 3. SHOW ALL OF YOUR WORK!

2 answers:

8 0

6(6/3)-2*3
You would take 6 times 6 then 6 times three. After that you would set your problem up like this
36/18-2*3 then you would take 2*3 which is six
Then it would be set up like so
36/18-6
You would then divide 36 and 18 which is two. Then take 2 minus 6 which is -4 so your answer would be -4.

klemol [59]3 years ago

5 0

Answer : 6

6(p<span>÷x) - 2x

6(6</span><span>÷3) - 2(3)

6(2) - 2(3)

12 - 6

6</span>

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You know only the given information about

katrin [286]

Since they are multiples if 12

The possibilities are

12, 12, 156

12,24,144

12,36,132

12,48,120

12,60,108

12,72,96

12,84,84

24,24,132

24,36,120

24,48,108

24,60,96

24,72,84

36,36,108

36,48,96

36,60,84

36,72,72

48,48,84

48,60,72

60,60,60

Hence the probability is 1/19 or 0.0526

6 0

3 years ago

HELP ASAP

serg [7]

The equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.

<h3>What is the equation of line?</h3>

The equation of the line is the way of representation of a line in the equation form.

The equitation of the lines represents the line by the set of points on which the line lies or passes through in the coordinate system.

The formula to find equation of line is,

(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)

Here, x and y are the coordinate and subscript (1,2) used for the first and second point.

The points from which the line passes through are (2,5) and (-2,-3). Put the values,

(y-y₁)={(y₂-y₁)/(x₂-x₁)}(x-x₁)

(y-(-2))={(-3-5)/(-2-2)}(x-2)

y+2={-8/-4}(x-2)

y+2=2(x-2)

y+2=2x-4

y=2x-4-2

y=2x-6

Thus, the equation of the line which is plotted on the graph and passes from the points (2,5) and (-2,-3) is y=2x-6.

Learn more about the equation of line here;

brainly.com/question/13763238

#SPJ1

3 0

2 years ago

The answers to these questions

I am Lyosha [343]

Answer:

The formula to find the radius is diameter/pie. Also, it does not show the formula that they are asking.

Step-by-step explanation:

8 0

3 years ago

(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$