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never [62]
3 years ago
9

PLEASE HELP FAST FOR BRAINLIEST

Mathematics
1 answer:
zysi [14]3 years ago
5 0

For this case we have a problem where we must apply the Ohm Law, this law states:

V = I * R

Where:

  • V: Voltage
  • I: Current
  • R: Resistance

The units of these three magnitudes in the international system of units are, respectively, volts (V), amps (A) and ohms (Ω).

According to the statement our data are:

I = 21 amps

R = 15ohms

We want to find the voltage, like this:

V = 21 * 15 (amps * ohms)

V = 315 volts

Answer:

V = 315 volts

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Serga [27]
The sums range from 2 to 12 of which 6 are even out of 11 possible sums.
There are 4 multiples of 3, two of which are odd.

So the number of even sums is 6 and there are 2 unique or odd multiples of 3.

So there are a total 6+2=8 outcomes we want out of 36 possible outcomes.

The probability is then 8/36 or 2/9
4 0
3 years ago
Solve for R. P=R−C What is R equal to?
kykrilka [37]

Answer:

R = P+C

Step-by-step explanation:

P = R-C

+C    +C

R = P+C

6 0
3 years ago
Which angle measures of 45°
ludmilkaskok [199]

Answer:

first

Step-by-step explanation:

half of right angle

5 0
3 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
How old am I if 400 reduced by 3 times my age is 241? Can I please have an explanation..
OLEGan [10]

Given :

400 reduced by 3 times my age is 241

To Find :

My age .

Solution :

Let, age is x .

So , expressing given condition mathematically , we get :

400-3x=241\\\\3x=400-241\\\\3x=159\\\\x = 53

Therefore, the age is 53 years.

Hence, this is the required solution.

7 0
3 years ago
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