Area of a parallelogram=base x heigth
Data:
base=(2x+3)
heigth=(ax+5)
area of this parallelogram=8x²+bx+15
Therefore:
8x²+bx+15=(2x+3)(ax+5)
8x²+bx+15=2ax²+10x+3ax+15
8x²+bx+15=2ax²+(10+3a)x+15
Then:
8x²=2ax²
a=(8x²)/(2x²)=4
bx=(10+3(4))x
bx=(10+12)x
b=22x/x=22
Answer: a=4 and b=22.
Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40.
From there use algebraic steps to find out what x is ( the break - even point ).
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40
0.855625x - 4x + 20 = 1.265625x + 6x + 40
-0.41x - 4x + 20 = 6x + 40
-4.41x + 20 = 6x + 40
20 = 10.41x + 40
-20 = 10.41x
-1.92122958694 = x
Rounded to the nearest tenth it's -1.9 = x.
Tell me if I got something wrong :)
7. -20
10 3
6 3
Subtract each remember 4-- -6= 10
<em>c. the least squares method. </em>
Regression equation:
In simple linear regression, the predicted value of the dependent variable is given by the equation = b0 + b1x. The values of b0 and b1 are calculated from the data so that the line = b0 + b1X minimizes the total sum of squared errors (error is the difference between the predicted value and the actual value of y).
Least squares method:
The least squares method is a statistical procedure to find the best fit for a set of data points by minimizing the sum of the offsets or residuals of points from the plotted curve.
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Answer:
Step-by-step explanation:
Matrix'is determinat:
X1 Y1
X2 Y2
D=(X1*Y2) - (X2*Y1)
D=(3X-4) - (-3*4)
D=0
Determinant of X
I 1 Y1
I 2 Y2
DX=( I 1 *Y2) - ( I 2*Y1)
DX= (14* -4) - (-14*4)
DX=0
Determinant of Y
X1 I 1
X2 I 2
DY= (X1 * I2) - (X2* I1)
DY=(3X-14) - (-3*14)
DY=0
The result of the variables are solved by:
X=DX/D.... Y=DY/D
X=0/0 Y=0/0
X=NaN Y=NaN