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tresset_1 [31]
3 years ago
10

Prove the divisibility:45^45·15^15 by 75^30

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

3^{75}.

Step-by-step explanation:

We have been an division problem: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(9*5)^{45}=9^{45}*5^{45}

15^{15}=(3*5)^{15}=3^{15}*5^{15}

75^{30}=(15*5)^{30}=15^{30}*5^{30}

Substituting these values in our division problem we will get,

\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}

\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}

\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}

\frac{3^{105}*5^{60}}{3^{30}*5^{60}}

\frac{3^{105}}{3^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{105}}{3^{30}}=3^{105-30}

3^{105-30}=3^{75}

Therefore, our resulting quotient will be 3^{75}.

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Write the equation of the line that passes through the given points<br> (0,2)) and (-9, -3)
Irina18 [472]

Step-by-step explanation:

Y= m x+ C

m (slope ) = 2 - (_3) / 0 _( - 9 )

= 5 / 9

( O, 2 ) Satisfying equation

2= 5/9 ( 0) + C

C= 2

So eq. is

y= 5/ 9 X + 2

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3 years ago
I need help for number 5. Plz
iogann1982 [59]
5/3 each friend gets 3/5 of the trail mix
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3 years ago
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
Read 2 more answers
2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for
nadezda [96]

The question is incomplete:

1. A cosmetologist must double his/her salary before the employer con realize any profit from  his/her work,  Miss, Mead paid Miss, Adams $125,00 per week to start.

2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for  services if Miss. Mead is to realize $50.00 profit on her work? (Conditions on salary are the same  as in problem 1)  

ODS

a. $275.00 b. $325.00 c. $250.00 d. $300.00

Answer:

d. $300.00

Step-by-step explanation:

Given that a cosmetologist must double her salary before the employer can realize any profit from  his/her work, for Miss. Mead to realize $50.00 profit on her work, you would have to determine the amount that doubles the salary of the cosmetologist and add the $50 needed as profit:

Salary= $125*2=$250

$250+$50= $300

According to this, the answer is that for Mead to realize $50.00 profit on her work, Miss. Brown must take $300.

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3 years ago
Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard
TiliK225 [7]

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

P(X > 550)=?

Solution:

P(X > 550)=1-P(X≤550)

=1-P(Ζ≤\frac{550-500}{50} )

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

#SPJ4

3 0
2 years ago
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