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rosijanka [135]
3 years ago
10

Two questions in 1 please help​

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

1 and idk the second

Step-by-step explanation:

You might be interested in
Select the correct answer.
ICE Princess25 [194]
The correct ois D. -17.5 degrees
Step-by-step explanation:
The daytime temperature in Apple Valley is
falling by 2.5 degrees each day
Therefore, Change in the temperature each day
=-2.5 degrees
Now, we need to find the net change in the daily
temperature after one calendar week
Now, number of days in one calendar week = 7
So, Net change in the daily temperature after
one calendar week = Daily change × Number of
days in one calendar week
Net change in the daily temperature after
one calendar week =-2.5 x7
# Net change in the daily temperature after
one calendar week =-17.5 degrees
Therefore, The correct option is -17.5
degrees
7 0
2 years ago
What’s 6+1 beacause I need to know pleaseee help
GenaCL600 [577]

Answer:

7

Step-by-step explanation

6+1=7

4 0
3 years ago
Read 3 more answers
Johnny rode his bike to a friends house 4 blocks down the street in his neighborhood. He Immediately rode back home once he real
Aneli [31]

Answer:

Total displacement = 0 blocks

Step-by-step explanation:

Displacement : It is defined as the total distance between the initial and the final positions of the moving object or a body. The total displacement can be 0 in case the initial and the final positions of the body are same.

The distance traveled by Johnny from his house to his friends house = 4 blocks

Then he immediately returns to his house, so the total distance then covered = 4 blocks

Total distance traveled = 4 + 4

                                        = 8 blocks

But the initial position of Johnny is his house and the final position of Johnny is also his house

Therefore, the initial and the final position of Johnny is same and this can be used as a reference point for the given problem.

⇒ Total displacement = 0 blocks

7 0
3 years ago
Square root of 2tanxcosx-tanx=0
kobusy [5.1K]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3242555

——————————

Solve the trigonometric equation:

\mathsf{\sqrt{2\,tan\,x\,cos\,x}-tan\,x=0}\\\\ \mathsf{\sqrt{2\cdot \dfrac{sin\,x}{cos\,x}\cdot cos\,x}-tan\,x=0}\\\\\\ \mathsf{\sqrt{2\cdot sin\,x}=tan\,x\qquad\quad(i)}


Restriction for the solution:

\left\{ \begin{array}{l} \mathsf{sin\,x\ge 0}\\\\ \mathsf{tan\,x\ge 0} \end{array} \right.


Square both sides of  (i):

\mathsf{(\sqrt{2\cdot sin\,x})^2=(tan\,x)^2}\\\\ \mathsf{2\cdot sin\,x=tan^2\,x}\\\\ \mathsf{2\cdot sin\,x-tan^2\,x=0}\\\\ \mathsf{\dfrac{2\cdot sin\,x\cdot cos^2\,x}{cos^2\,x}-\dfrac{sin^2\,x}{cos^2\,x}=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left(2\,cos^2\,x-sin\,x \right )=0\qquad\quad but~~cos^2 x=1-sin^2 x}

\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}


Let

\mathsf{sin\,x=t\qquad (0\le t


So the equation becomes

\mathsf{t\cdot (2t^2+t-2)=0\qquad\quad (ii)}\\\\ \begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{2t^2+t-2=0} \end{array}


Solving the quadratic equation:

\mathsf{2t^2+t-2=0}\quad\longrightarrow\quad\left\{ \begin{array}{l} \mathsf{a=2}\\ \mathsf{b=1}\\ \mathsf{c=-2} \end{array} \right.


\mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=1^2-4\cdot 2\cdot (-2)}\\\\ \mathsf{\Delta=1+16}\\\\ \mathsf{\Delta=17}


\mathsf{t=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{2\cdot 2}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{4}}\\\\\\ \begin{array}{rcl} \mathsf{t=\dfrac{-1+\sqrt{17}}{4}}&\textsf{ or }&\mathsf{t=\dfrac{-1-\sqrt{17}}{4}} \end{array}


You can discard the negative value for  t. So the solution for  (ii)  is

\begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{t=\dfrac{\sqrt{17}-1}{4}} \end{array}


Substitute back for  t = sin x.  Remember the restriction for  x:

\begin{array}{rcl} \mathsf{sin\,x=0}&\textsf{ or }&\mathsf{sin\,x=\dfrac{\sqrt{17}-1}{4}}\\\\ \mathsf{x=0+k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=arcsin\bigg(\dfrac{\sqrt{17}-1}{4}\bigg)+k\cdot 360^\circ}\\\\\\ \mathsf{x=k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=51.33^\circ +k\cdot 360^\circ}\quad\longleftarrow\quad\textsf{solution.} \end{array}

where  k  is an integer.


I hope this helps. =)

3 0
3 years ago
Help asap please and please explain so I could try the rest on my own
kiruha [24]

Answer:

7

Step-by-step explanation:

It has a 45 45 90 ratio, so if the hypotenuse is 7 root 2, then the two sides have to be 7.

4 0
2 years ago
Read 2 more answers
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