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GrogVix [38]
3 years ago
10

Please help. I don’t remember how to do this.

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

Answer:

1.5 hours

Step-by-step explanation:

65% ---- 1 hour

1% ---- 1/65 hours

100% ---- 1/65 ×100 = 1.5 hours (nearest half-hour)

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Which symbols correctly relates the 2 numbers 55?35
Sholpan [36]

Answer:

>

Step-by-step explanation:

55 is greater than 35, so the open "mouth" of the greater than sign should go towards 55.

8 0
4 years ago
Read 2 more answers
Jack planted 1 1/4 rows of lettuce in the family garden, Rose planted 1 1/2 rows of broccoli and Calvin planted 4 5/12 rows of b
Oksana_A [137]

Solution:

we are given that

Jack planted 1 1/4 rows of lettuce in the family garden.

Rose planted 1 1/2 rows of broccoli and Calvin planted 4 5/12 rows of beans.

we have been asked to find -How many rows were planted in the garden?

To find this , we will add all the numbers of rows planted.

Hence number of rows planted

=1\frac{1}{4}+ 1\frac{1}{2}+4\frac{5}{12}\\\\=2\frac{1+2}{4}+ 4\frac{5}{12}\\\\=2\frac{3}{4}+ 4\frac{5}{12}\\\\=7\frac{1}{6}   \\

5 0
4 years ago
Read 2 more answers
The area of an isosoles trapezoid is 45cm squared, and it's height is 5cm. Find the perimeter if the length of a leg is 2/3 of t
Schach [20]

Answer:

Perimeter = 42 cm.

Step-by-step explanation:

The  2 legs are equal in length as it is an isosceles trapezoid.

Area of  trapezoid  = (h/2)(a + b)  where a and b are the parallel bases.

So

(5/2) (a + b) = 45

a + b = 45 * 2/5 = 18 cm.

We are given that the length of a leg (L) is 2/3 * sum of the bases, so:

L = 2/3(a + b)

  = 2/3 * 18

   = 12 cm.

The perimeter = a + b + 2L

= 18 * 2*12

= 42 cm.

3 0
2 years ago
I need help. Please give me an example
xxTIMURxx [149]

Answer:

9

Step-by-step explanation:

3/729= 9

729=9^3

=3/9^3= 9


Hope this helps! Please give brainiest!

8 0
3 years ago
The attractive electric force between point charges q and -2q has a magnitude of 2.2 N when the separation
swat32

Answer:

The Magnitude of charge = q = 15.47 micro coulomb  

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F = (k \frac{q1 q2}{r^{2}})  where k= 9 \times 10^{9} \frac{N m^{2}}{c^{2}}

So , 2.2 = 9 \times 10^{9} ( (\frac{(q) ( - 2q)}{1.4^{2}})

So , q ² = (\frac{0.479 \times 10^{-9}}{-2})

      For charge magnitude

   I.e q ² = 2.395 \times 10^{-10}

 so, q =  1.547 \times 10^{-5}

      q = 15.47 \times 10^{-6} c

Or,  q = 15.47 micro coulomb

Hence  the Magnitude of charge = q = 15.47 micro coulomb   Answer

4 0
4 years ago
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