We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
Answer:
It is <em>a</em> solution, one of an infinite number of solutions.
Step-by-step explanation:
You can check to see if the given point is in the solution set:
4(-4) +5(4) = -16 +20 = 4 > -6 . . . . yes
-2(-4) +7(4) = 8 +28 = 36 > 20 . . . yes
The offered point satisfies both inequalities, so is in the solution set. It is not <em>the</em> solution, but is one of an infinite number of solutions.
Answer: B. 77
Sub x =6 into the given expression
4x^2 - 12x + 5
= 4(6)^2 - 12(6) + 5
= 144 - 72 + 5
= 77
Answer:
1800
Step-by-step explanation:
→ First of all we need to find the prime factorisation of the numbers.
18 = 2 × 3 × 3 or 2 × 3²
40 = 2 × 2 × 2 × 5 or 2³ × 5
75 = 3 × 5 × 5 or 5² × 3
→ Now find the number that appear twice or more and write them down
3 and 3 from 18
2, 2 and 2 from 40
5 and 5 from 75
→ Now multiply all of these numbers together
3 × 3 × 2 × 2 × 2 × 5 × 5 = 3² × 2³ × 5² = 1800
Answer:
2 2/3
Step-by-step explanation:
hope this helps :)
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