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mr Goodwill [35]
3 years ago
7

Viewpoint Company’s October 31 inventory was destroyed by fire. The company’s beginning inventory was $500,000, and purchases fo

r January through October were $1,200,000. Sales for the same period were $1,800,000. The company’s normal gross profit percentage is 30% of sales. Using the gross profit method, the October 31 inventory is estimated to be $300,000. $40,000. $540,000. $440,000.
Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

$440,000

Step-by-step explanation:

                                           Sales : $1,800,000

Gross profit : (30% × 1,800,000) :   $540,000

Cost of goods sold (Sales-profit) : $1260,000

Beginning inventory   :   $500,000

Purchasing                  : $1,200,000

Total                            :  $1,700,000

Goods sold (subtract) : $1,260,000

Closing inventory       :   $440,000

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Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving
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Answer:

The volume of the solid is 714.887 units³

Step-by-step explanation:

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- Consider a region in the plane that is divided into thin vertical

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- If each vertical rectangle is revolved about the y-axis, we

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- The resulting volume of the cylindrical shell is the surface area

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* Lets solve the problem

∵ y = x^{\frac{5}{2}}

∵ The plane region is revolving about the y-axis

∵ y = 32 and x = 0

- Lets find the volume by the shell method

- The definite integral are x = 0 and the value of x when y = 32

- Lets find the value of x when y = 0

∵ y = x^{\frac{5}{2}}

∵ y = 32

∴ 32=x^{\frac{5}{2}}

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∴ x=(32)^{\frac{2}{5}}=4

∴ The definite integral are x = 0 , x = 4

- Now we will use the rule

∵ V = \int\limits^a_b {2\pi}xf(x) \, dx

∵ y = f(x) = x^(5/2) , a = 4 , b = 0

∴ V=2\pi \int\limits^4_0 {x}.x^{\frac{5}{2}}\, dx

- simplify x(x^5/2) by adding their power

∴ V = 2\pi \int\limits^4_0 {x^{\frac{7}{2}}} \, dx

- The rule of integration of x^{n} is ==== \frac{x^{n+1}}{(n+1)}

∴ V = 2\pi \int\limits^4_0 {x^{\frac{9}{2}}} \, dx=2\pi[\frac{x^{\frac{9}{2}}}{\frac{9}{2}}] from x = 0 to x = 4

∴ V=2\pi[\frac{2}{9}x^{\frac{9}{2}}] from x = 0 to x = 4

- Substitute x = 4 and x = 0

∴ V=2\pi[\frac{2}{9}(4)^{\frac{9}{2}}-\frac{2}{9}(0)^{\frac{9}{2}}}]=2\pi[\frac{1024}{9}-0]

∴ V=\frac{2048}{9}\pi=714.887

* The volume of the solid is 714.887 units³

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