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spayn [35]
3 years ago
5

In a single period order quantity model, if the shortage cost is four times the overage cost, then, (A) what is the optimal serv

ice level (i.e., critical fractile)?, and (B) using the optimal service level from part (A), what is the optimal order quantity if the demand is normally distributed with a mean of 70 and variance of 9? Round your final answer to the nearest integer.
Business
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

If immature value is on top of an average prices, it implies that if the vendor isn't ready to offer the merchandises on demand the loss are going to be four times than value of the product sustains in record. So, it's suggest-able that sustain record in stores supported demand.

a) The optimum service level are going to be 95%

b) 79 units will be the optimal order quantity.

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A structure that organizes worldwide operations primarily based on function and secondarily on product is called: a global area
Tatiana [17]

Answer:

a global functional division.

Explanation:

In a global functional structure, the MNC activities are to be organized among the particular functions that are related to the production, finance, marketing etc. Here the developments are establishment that would have the responsibility worldwide for the particular function

So as per the given situation, the above should be the answer

8 0
2 years ago
The formula for the production budget is budgeted sales in units plus desired ending merchandise inventory less beginning mercha
Deffense [45]

Answer:

desired ending finished goods units less beginning finished goods units.

Explanation:

production budget can be regarded as budget that gives the calculation of the number of units of particular products which is needed to be manufactured, this is comprises the sales forecast as well as amount of finished goods inventory that is planned to have on hand.

It should be noted that the formula for the production budget is desired ending finished goods units less beginning finished goods units..

7 0
2 years ago
Robert Sampson owns a townhouse valued at $185,000 and still has an unpaid mortgage of $150,000. In addition to his mortgage, he
AlexFokin [52]

Answer:

0.31

Explanation:

Given that,

Visa = $ 755

MasterCard = 380

Discover card = 555

Education loan = 3,900

Personal bank loan = 650

Auto loan =  6,000

Total debt  (not including mortgage) = $12,240

Net Worth (not including home) = $39,000

Robert's debt-to-equity ratio:

= Total debt ÷ Net worth

= $12,240 ÷ $39,000

= 0.31

8 0
3 years ago
Elsa participates in an investigation into possible violations of the Civil Rights Act of 1964 at Fabrication Foundry, Inc., whe
Sedbober [7]

Answer:

The correct answer is letter "D": disparate-impact discrimination claim.

Explanation:

A disparate-impact discrimination claim is one filed because there is a presumed act of unintentional discrimination at work. This could be the result of requesting employees with certain abilities which disfavors a sector of the workforce of the firm. The company has to prove the feature requested for the job position is necessary for the regular development of the activities if such position.

3 0
3 years ago
Consider the three mutually exclusive alternatives below. Determine which alternative is preferable at an interest rate of 9% pe
laila [671]

Answer:

a. AW, A($) = 79646

b. AW, B ($) =  29,367

c. AW, C ($) = 80738

Explanation:

Solution:

First of let's sort out the data given for all three alternatives:

Alternative A:

Capital Investment = $400,000

Annual Expense = $189,000

Annual Revenue = $309,000

Salvage Value = $65,000

Life = 24 Years

Alternative B:

Capital Investment = $230,000

Annual Expense = $122,500

Annual Revenue = $222,500

Salvage Value = $180,000

Life = 5 Years

Alternative C:

Capital Investment = $150,000

Annual Expense = $134,000

Annual Revenue = $234,000

Salvage Value = $130,000

Life = 12 Years

a.

AW, A($) = - 400,000 x A/P(9%, 24) + (309,000 - 189,000) + 65,000 x P/F(9%, 24) x A/P(9%, 24)

AW, A($) = - 400,000 x 0.103 + 120,000 + 65,000 x 0.1264 x 0.103

AW, A($) = - 41,200 + 120,000 + 846.25

AW, A($) = 79646

b.

AW, B ($) = -230,000  x A/P(9%, 5) + (222,500 - 134,000)

AW, B ($) = -230,000  x 0.2571 + (222,500 - 134,000)

AW, B ($) =  29,367

c.  

AW, C ($) = - 150,000 x A/P(9%, 12) + (234,000 - 134,000) + 130,000 x P/F(9%, 12) x A/P(9%, 12)

AW, C ($) = - 150,000 x 0.1397 + 100,000 + 130,000 x 0.3555 x 0.1397

AW, C ($) = - 20,955 + 100,000 + 1,692.50

AW, C ($) = 80738

7 0
2 years ago
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