3x^2+6x^2-4x-8 = 3x^2(x + 2) - 2(x + 2) = (x + 2)( 3x^2 - 2) = 3(x+2)(x - 
)(x + )
Can anyone solve this? I'm having a couple of complications.x=6 y=8 z=3
1 answer:
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