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Ivan
2 years ago
5

s there a dilation that maps shape II onto shape I? If so, what is the scale factor and is it an enlargement or a reduction?

Mathematics
1 answer:
Agata [3.3K]2 years ago
7 0

Answer:

Enlargement.

Scale Factor: 3

Step-by-step explanation:

Use points to find the enlargement. Typically, you will use all the points.

A(1 , 1) ⇒ A'(3 , 3)

B(2 , 1) ⇒ B'(6 , 3)

C(1 , 2) ⇒ C'(3 , 6)

D(2 , 2) ⇒ D'(6 , 6)

To find the scale factor, simply divide the Point' with the original Point. Use any number.

A'(3 , 3)/(A(1 , 1)) = 3

B'(6 , 3)/(B(2 , 1)) = 3

C'(3 , 6)/(C(1 , 2)) = 3

D'(6 , 6)/(D(2 , 2)) = 3

Your scale factor is 3.

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3 years ago
Which ordered pair would form a proportional relationship with the point graphed below?
nevsk [136]

Answer:

(90,60)

Step-by-step explanation:

if you look closely through the linear graph, the line crosses through (90,60) and not the other given pairs.

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Read 2 more answers
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

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V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
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liq [111]

Answer:

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Step-by-step explanation:

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8 0
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