The percent markup is 62.5%
The work is provided in the image attached.
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
<u>With parentheses:</u>
(3 - 4)(4 + 5)/3
<u>Without parentheses:</u>
7 + 6 - 11 × 2
Hope this helps! :)
Hypotenuse² = perpendicular² + base²
H² = 20²+21²
H²= 400+441 = 841
H = √841
H = 29 cm
