The perimeter of the equilateral triangle will be 76.2 in
<u>Explanation:</u>
Altitude of an equilateral triangle, H = 22 in
Perimeter, p = ?
Let a be the side of the triangle
We know:
Perimeter = 3a
P = 3 X 25.4 in
P = 76.2 in
An offshore lighthouse is 2 kilometers from a Coast Guard station C and 2.5 kilometers from a hospital H near the shoreline. If
the angle formed by light beams to C and H is 143o, what is the distance CH (by sea) between the Coast Guard station and the hospital?
1 answer:
Answer:
4.3 km
Step-by-step explanation:
The law of cosines can be used to find the desired distance. If we call the lighthouse position point L, then we have ...
CH² = LC² +LH² -2·LC·LH·cos(L)
CH² = 2² +2.5² -2·2·2.5·cos(143°) = 10.25 -10cos(143°) ≈ 18.2364
CH ≈ √18.2364 ≈ 4.27 . . . . km
The distance CH is about 4.3 km.
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