An offshore lighthouse is 2 kilometers from a Coast Guard station C and 2.5 kilometers from a hospital H near the shoreline. If
the angle formed by light beams to C and H is 143o, what is the distance CH (by sea) between the Coast Guard station and the hospital?
1 answer:
Answer:
4.3 km
Step-by-step explanation:
The law of cosines can be used to find the desired distance. If we call the lighthouse position point L, then we have ...
CH² = LC² +LH² -2·LC·LH·cos(L)
CH² = 2² +2.5² -2·2·2.5·cos(143°) = 10.25 -10cos(143°) ≈ 18.2364
CH ≈ √18.2364 ≈ 4.27 . . . . km
The distance CH is about 4.3 km.
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Answer:
hello :
the area is : A= w ×l ... w : the width l : the length
A = 323 l = 19 w ?
l = A/w
l = 323/ 19
l = 17 feet
get a common denominator of 18
5/6 * 3/3 +4/9 * 2/2 - -2*18/18
15/18 +8/18 + 36/18
23/18 + 36/18
59/18
change to a mixed number
18 goes into 59 3 times with 5 left over
3 and 5 /18
I think it would best be displayed as a line plot.
Why even ask the question if you know the answer??
Answer:
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Step-by-step explanation:
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