An offshore lighthouse is 2 kilometers from a Coast Guard station C and 2.5 kilometers from a hospital H near the shoreline. If
the angle formed by light beams to C and H is 143o, what is the distance CH (by sea) between the Coast Guard station and the hospital?
1 answer:
Answer:
4.3 km
Step-by-step explanation:
The law of cosines can be used to find the desired distance. If we call the lighthouse position point L, then we have ...
CH² = LC² +LH² -2·LC·LH·cos(L)
CH² = 2² +2.5² -2·2·2.5·cos(143°) = 10.25 -10cos(143°) ≈ 18.2364
CH ≈ √18.2364 ≈ 4.27 . . . . km
The distance CH is about 4.3 km.
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Hey there, Lets solve this problem together.
Our first step will be to g<span>ather like terms
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<span>
Simplify 5×−2k×k to −5×2k×k
</span>
Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2
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<span><span><span>
</span></span></span>
Our first step will be to g<span>ather like terms
</span>
<span>
Simplify 5×−2k×k to −5×2k×k
</span>
Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2
</span></span></span>
</span></span></span>