A.) If there are no restrictions, Number of committes possible = 9C5 = 126
b.) If both Jim and Mary must be in the committee, then we are now choosing 3 persons from the remaining 7 people. So the number of committes possible = 7C3 = 35
c.) If either Jim or Mary (but not both) must be on the committe, then there are 7 people availabe and 4 choices to make after taking either Jim or Mary. Also, there are 2 possible ways of choosing either Jim or May.
Theefore, Number of committe possible = 2(7C4) = 2(35) = 70
A. 3
b. 4
c. 5
d. 8
Would you like an explaination?
♧
Just add the two fractions together 1/4 + 7/4 and you will get 2 so it would be 2 pounds all together
Answer:
00.5 is a answer A IS A ANSWER
Answer:
area if sector= teeta. ×πr²
360
<u>120</u>°. ×<u>2</u><u>2</u>×9×9
360. 7
<u>3×1782</u>
7
5346
