Question

i need help!!! write an equation in point-slope form of the line through point j(4, –4) with slope 4. a. y 4=4(x 4) b. y 4=4(x-4) c. y-4=4(x 4) d. y 4=4(x-4)

Answer 1

Required equation is y - y1 = m(x - x1); where m = 4 and (x1, y1) = (4, -4)
y - (-4) = 4(x - 4)
y + 4 = 4(x - 4)

Answer 2

Answer:

The equation of line passing through (4,-4) and having slope '4' is: $y+4=4(x-4)$

Step-by-step explanation:

The equation of a line passing through a point $(x_{1},y_{1})$ and having slope 'm' is given by:

$y-y_{1} =m(x-x_{1})$

Here we are given that the line passes through the point (4,-4) and having slope 4.

⇒   $(x_{1},y_{1})=(4,-4)$  and $m=4$

Hence, the equation of line is:

$y+4=4(x-4)$