What is the distance between between 120 and -50 on the number line
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Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,
Consider right triangle ABE, by the Pythagorean theorem
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