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3 years ago

I need step by step instructions on how to get the y-intercept for the following function:

Mathematics

1 answer:

Svetllana [295]3 years ago

4 0

Luktdkilfdiykfg;oizxkuilouyk7it8rl,kvkuc kugc ulv lug

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A survey found that women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also

Effectus [21]

Answer: 99.51%

Step-by-step explanation:

Given : A survey found that women's heights are normally distributed.

Population mean : $\mu =63.2 \text{ inches}$

Standard deviation: $\sigma= 2.4\text{ inches}$

Minimum height = 4ft. 9 in.= $4\times12+9\text{ in.}=57\text{ in.}$

Maximum height = 6ft. 2 in.= $6\times12+2\text{ in.}=74\text{ in.}$

Let x be the random variable that represent the women's height.

z-score : $z=\dfrac{x-\mu}{\sigma}$

For x=57, we have

$z=\dfrac{57-63.2}{2.4}\approx-2.58$

For x=74, we have

$z=\dfrac{74-63.2}{2.4}\approx4.5$

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

$P(-2.58$

Hence, the percentage of women meeting the height requirement = 99.51%

8 0

3 years ago

LAST QUESTION SEND HELP!!!!

dangina [55]

The answer is D. because you use Pythagoreans theory and do 12^2+23^2 which equals 673, then you root it and get 26.

7 0

3 years ago

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Your classroom received 150 books. You are placing them in bins. Each bin holds 20 books. How many bins do you need? Remainder:

Mazyrski [523]

Answer:

you need 8 bins because 150/20 is 7.5 but you can't have half a bin and you need somewhere to put the other books

8 0

3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

6 0

3 years ago

What is -1/3 minus 5/8

Tom [10]

- 1/3 -5/8
-8/24 - 15/24
-23/24

The first step is to find the least common denominator. The LCD of 3 and 8 is 24. Now, mulitply -1/3 by 8/8 and -5/8 by 3/3. This will give you fractions with equal denominators which you need to find before subtracting. Finally, you simplify the equation. Since this cannot be simplified, -23/24 is the answer

5 0

3 years ago

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