3 years ago

ASAP

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

7 0

Answer:

$\frac{x+12}{4(x+3)}$

Step-by-step explanation:

we have

$(\frac{3}{x} +\frac{1}{4}):(1+\frac{3}{x})$

Multiply by 4x numerator and denominator to remove the fractions

$(\frac{3}{x}(4x) +\frac{1}{4}(4x)):(1(4x)+\frac{3}{x}(4x))$

$\frac{12+x}{4x+12}$

Factor 4 in the denominator

$\frac{x+12}{4(x+3)}$

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9.21 <img src="https://tex.z-dn.net/?f=9.21%20%5Cdiv%200.4%20%3D%20" id="TexFormula1" title="9.21 \div 0.4 = " alt="9.21 \di

Whitepunk [10]

Let us do it by converting the 0.4 to a fraction, it has one decimal, so we'll use one zero at the denominator.

and 9.21 to a fraction as well, two decimals, thus two zeros at the denominator then,

$\bf 9.21\div 0.4\\\\
-------------------------------\\\\
0.\underline{4}\implies \cfrac{04}{1\underline{0}}\implies \cfrac{4}{10}\implies \cfrac{2}{5}\qquad \qquad \qquad \qquad 9.\underline{21}\implies \cfrac{921}{1\underline{00}}\\\\
-------------------------------\\\\
9.21\div 0.4\implies \cfrac{921}{100}\div \cfrac{2}{5}\implies \cfrac{921}{100}\cdot \cfrac{5}{2}\implies \cfrac{921}{20}\cdot \cfrac{1}{2}\implies \cfrac{921}{40}
\\\\\\
23\frac{1}{40}\implies 23.025$

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