Question

ASAP

Answer 1

Answer:

$\frac{x+12}{4(x+3)}$

Step-by-step explanation:

we have

$(\frac{3}{x} +\frac{1}{4}):(1+\frac{3}{x})$

Multiply by 4x numerator and denominator to remove the fractions

$(\frac{3}{x}(4x) +\frac{1}{4}(4x)):(1(4x)+\frac{3}{x}(4x))$

$\frac{12+x}{4x+12}$

Factor 4 in the denominator

$\frac{x+12}{4(x+3)}$