DB/dt = k*B
dB/(kB) = dt
Integrating both sides:
1/k*ln|B| = t + C
B = C*e^(kt)
At time t = 0, B = 4000 and at time t = 3 (3 hours past 9 AM), B = 4500
4000 = C
4500 = 4000*e^(3k) => k = 1/3*ln(9/8)
At time t = 15 (Midnight), B = 4000*e^(1/3*ln(9/8)*15) = 4000*(9/8)^5 = 7208 bacteria
So first you need to find a formula for who has what!
Because nobody said what chase had, chase is our variable!
Chase = x
Sophie = x-6 (six less than Chase so subtraction)
Jonah = x•3 (three times the amount of Chase)
Now you will put all of this in an equation- adding everybody together! The total is 89 so that will be what’s after the equal sign!
Your equation: x+x-6+x•3=89
First you will use PEMDAS, since there are no parentheses or exponents- you’ll do multiplication first!
x+x-6+(x•3)=89
When you multiply that out, you will be left with: x+x-6+3x=89
Second you will add all common terms! Remember- the 3x means there are THREE x’s in that one spot. Take out all x’s in the equation and add them together!
x+x+3x=5x
Now you are left with:
5x-6=89
Now you will solve this like a regular equation! First, you have to move the -6 to the right so you will do the inverse operation (the opposite sign) and add 6 to both sides! 89+6 is 95 and -6+6 is 0, so the 6 on the left cancels out and isn’t there anymore!
Now you have 5x=95. To get the x by itself, you will divide both sides by 5! (Once again, doing the inverse operation! Since 5 and x are being multiplied, you have to divide.)
When you divide, you are left with x=19. In this question, the answer is:
Each person has $19.
-4u = <24,-4>;
2v = <-10,4>;
<24,-4> + <-10,4> = <14,0>;
