ANSWER
EXPLANATION
The outermost square tile has side length,
The area of a square is given by;
We substitite the given expression for the side length into the formula to obtain,
We expand using the distributive property to obtain;
This gives us:
The last choice is correct.
Answer:
The slope for the parallel line to the equation -10x-5y=25 is -2
Step-by-step explanation:
First we need to convert the equation to slope-intercept form to determine the slope.
-10x-5y=25
+10x _10x
-5y=25+10x
/-5 /-5
y= -5 -2x
Remember, -5 is the y-intercept and -2 is the slope for this equation. A parallel line is a line that never intersects with the first line. If the two equations have different slopes, they will eventually intersect. Because of this, our parallel line needs to have the same slope as the initial equation: -10x-5y=25
Since we've determined that the slope for that equation is -2, we can infer that this will be the slope for our parallel line.
The roots routine will return a column vector containing the roots of a polynomial. The general syntax is
z = roots(p)
where p is a vector containing the coefficients of the polynomial ordered in descending powers.
Given a vector
which describes a polynomial
we construct the companion matrix (which has a characteristic polynomial matching the polynomial described by p), and then find the eigenvalues of it (which are the roots of its characteristic polynomial)
Example
Here is an example of finding the roots to the polynomial
--> roots([1 -6 -72 -27])
ans =
12.1229
-5.7345
-0.3884
Answer:
Step-by-step explanation:
The square in the middle has a length and width of 3, so multiply. <u>9</u>.
All of the triangles have a base of 3 and a height of 2. The area equation for triangles is
So base*height is 6. Divide that by 2 or multiply by 1/2.
You get 3. There are 4 triangles, so multiply <em>that</em> by 4. <u>12</u>.
Add 12 and 9 together, and you get:
I hope this helps!
Although the given statements are missing, the student's step-by-step solution is correct. The student had aimed to isolate the unknown variable in order to solve it. The student made sure the first step was to leave only one term in the side with the variable, before simplifying fractions.
