WILL MARK BRAINLIEST 50 POINTS PLEASE HELp

amelia needs to buy some cat food at the nearest store 2 bags of cat food is 6.50. How much would it be if amelia bought 3 bags?

tresset_1 [31]

Answer:

$9.75

Step-by-step explanation:

We have all we need to solve for Bag #3.

2 bags equal $6.50.

We want 3 bags, not 4. So we need to divide the original cost by 1/2.

$6.50 divided by 1/2 is $3.25

Now we add an additional $3.25 to the original $6.50

7 0

3 years ago

If f(x) = –x + 2, find f(4).

NeTakaya

Answer:

-2

Step-by-step explanation:

If you substitute x for 4, you have -4+2 to get -2.

3 0

3 years ago

Help! Simplify the following expression

Taya2010 [7]

Step-by-step explanation:

1/625×15625

We wil add power 2 as shown in the bracket

It will be 1/390625×244140625=625

3 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

Identify the level of measurement of the data, and explain what is wrong with the given calculation. In a survey, the favorite

Trava [24]

Answer:

The data are at the <u>Nominal</u> level of measurement.

The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.

Step-by-step explanation:

The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.

a)

The data are at the <u> Nominal </u> level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else

b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.

The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).

6 0

3 years ago