So, start by calculating how much acid you have in your starting solution
25
L solution
⋅
60 L acid
100
L solution
=
15 L acid
Let's say that
x
denotes the volume of pure acid that you must add to your starting solution. Since you're dealing with pure acid, the volume of acid will Increase by
x
V
acid
=
15
+
x
At the same time, the volume of the solution will also incrase by
x
V
sol
=
25
+
x
This means that the target solution's percent concetration by volume will be equal to
V
acid
V
soL
⋅
100
=
75
%
(
15
+
x
)
L
(
25
+
x
)
L
⋅
100
=
75
%
Solve this equation for
x
to get
(
15
+
x
)
⋅
100
=
(
25
+
x
)
⋅
75
1500
+
100
x
=
1875
+
75
x
25
x
=
375
⇒
x
=
375
25
=
15 L
So, if you add 15 L of pure acid to 25 L of 60% v/v acid solution, you'll get 40 L of 75% v/v acid solution.
Answer:
994.5
Step-by-step explanation:
First, you need to figure out how many people are actually attending the event. It says that there are 50% more so we are going to have to add 56% of 150 to 150.
150 x 0.56 = 84
150 + 84 = 234
Now, we have to multiply this by 4.25, because this is the cost of the food per person.
234 x 4.25 = 994.5
Answer:
e
Step-by-step explanation:
O,T,T,F,F,S,S
one
two
three
four
five
six
seven
eight
Given:
V = 5x² + 15x + 2, the volume
h = 5x, the height
Let A = the area of the base.
Because V = Ah, therefore
A*(5x) = 5x² + 15x + 2
![A = \frac{5x^{2}+15x+2}{5x}](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cfrac%7B5x%5E%7B2%7D%2B15x%2B2%7D%7B5x%7D%20)
Answer:
Answer:
0.16
Step-by-step explanation: