That would be 6.64 / 1.35 = 4.9 times (to the nearest tenth.)
Answer:
The Answer to your question is 1.
Step-by-step explanation:
Teagan is correct in using a division expression because Four-fifths is less than 1.
Answer:
189 components must be sampled.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.575.
Now, find the margin of error M as such

Assume that component lifetimes are normally distributed with population standard deviation of 16 hours.
This means that 
How many components must be sampled so that a 99% confidence interval will have margin of error of 3 hours?
n components must be sampled.
n is found when M = 3. So






Rounding up:
189 components must be sampled.
<span>As we know that 1 µm = 10^-6 m On squaring both sides 1 µm2 = 10^-6 x10^-6 m2 1 µm2 = 10^-12 m2</span>
An easier way of doing this would be to subtract the initial attitude from the final attitude and divide by the rate of increase
= 30000 - 6000÷4000
= 24000÷4000
=6mins