Answer:
2xy4 • (11x2 + 14xy + 17)
Step-by-step explanation:
(((22•(x3))•(y4))+((28•(x2))•(y5)))+(2•17xy4)
(((22•(x3))•(y4))+((22•7x2)•y5))+(2•17xy4)
(((2•11x3) • y4) + (22•7x2y5)) + (2•17xy4)
5.1 Pull out like factors :
22x3y4 + 28x2y5 + 34xy4 = 2xy4 • (11x2 + 14xy + 17)
Trying to factor a multi variable polynomial :
5.2 Factoring 11x2 + 14xy + 17
Final result :
2xy4 • (11x2 + 14xy + 17)
h - length of the hypotenuse
Use the Pyhagorean theorem:
9514 1404 393
Answer:
-2cos²(x) +3cos(x) -1
Step-by-step explanation:
Use the "Pythagorean identity" to replace sin²(x).
sin²(x) +cos²(x) = 1
Then ...
2sin²(x) +3cos(x) -3 = 2(1 -cos²(x)) +3cos(x) -3
= -2cos²(x) +3cos(x) -1
Answer:
Where are the box plots?? I need it to answer the question.
Answer: -0.10
Step-by-step explanation:
there is a pattern because 2014 0.45, 2015 0.20, 2016 0.35, 2016 0.10.
