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3 years ago

What is the answer to thus problem z=y-x

Mathematics

2 answers:

Margaret [11]3 years ago

8 0

1=1,y=3,z=2 that is the answer

anastassius [24]3 years ago

6 0

The only answers that are possible is z=y-x y=x+z or x=y-z

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Find the value of 4^2 + 6 ÷ 2

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Answer:

Step-by-step explanation:

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4^2 + 6 ÷ 2

16 + 6 ÷ 2

16 + 3

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3 years ago

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The students in Mrs. Smith's class placed 26 math textbooks on a scale. The scale indicated a weight of 1,248 ounces. Each math

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Step-by-step explanation:

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2 years ago

Domain and range of graphs

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3 years ago

Write an expression that is equivalent to - 0.5(14a - 22) .

PSYCHO15rus [73]

$\textsf{Hey \: there}$

<h2>QUESTION</h2>

$\mathsf{-0.5(14a - 22)}$

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

$\mathsf{(-0.5)(14a) + (-0.5)( -22)}$

<h2>SOLVING FOR OUR ANSWER</h2>

$\mathsf{(0.5)(14a) = - 7a} \\ \\ \mathsf{( - 0.5)( - 22) = 11}$

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

$\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{ \bf- 7a + 11}}} \checkmark$

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

$\dfrac{\frak{LoveYourselfFirst}}{:)}$

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

$\text{a(b + c)} \\ \text{a(b) + a(c)} \\ \text{a(b) = ab} \\ \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}$

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3 years ago

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago