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3 years ago

The sum of two numbers is 60 . The smaller number is 12 less than the larger number. What are the numbers?

Mathematics

1 answer:

statuscvo [17]3 years ago

5 0

Answer:

36 and 24

Step-by-step explanation

36 - 24 = 12

36 + 24 = 60

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Solve this for Brainliest! See the attachment [Level - GCSE]

madreJ [45]

Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

$x = 3 + 4\sqrt{3} = 9.928(4s.f.)$

$x = 3 - 4\sqrt{3} = -3.928(4s.f.)$ (Length can't be negative)

∴ $x = 3 + 4\sqrt{3}$

3 0

2 years ago

Read 2 more answers

Seven times the difference of a number 5 is 6

mamaluj [8]

The answer is 7(x-5)=6

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2 years ago

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dose choosing a blue marble rwpresent the complment event of choosing a red marble? Explain. help plz and thx

denis23 [38]

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2 years ago

James is 6 times older than his friend Zach . If Zach added 8 to his age and multiplied this sum by 3 . Write an equation that c

swat32

Given that:

James is 6 times older than his friend Zach, if Zach added 8 to his age and multiplied this sum by 3 .

To find:

The equation that can be used to solve for zach's age.

Solution:

Let the age of zach be Z.

Zach added 8 to his age = Z+8

And multiplied this sum by 3 = 3(Z+8)

James is 6 times older than his friend Zach = 6Z

Now,

$6Z=3(Z+8)$

$6Z-3Z=24$

$3Z=24$

Divide both sides by 3.

$Z=8$

Therefore, the required equation is $6Z=3(Z+8)$ is age of zach is 8 years.

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3 years ago

A survey asked a group of students to choose their favorite type of sport from the choices of soccer, softball, basketball, and

jolli1 [7]

The answer would be 12 students. 8+4+6+3=21.
84 divided by 21 would = 4.
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2 years ago