Answer:
Given Acousting power P=2.35*10^5W
Distance r=51.3m
Area=4πr^2=4*3.142*51.3^2=33075.08
Sound intenstity I= (2.35*10^5)/33075.08=6962.8W/m^Reference sound intenstity Io=10^-12w/m^2
Sound intenstity I1=10*log(I/Io)
10*log(6962.8/10^-12)db =24.5w/m^2
Answer:electrostatic interactions, hydrogen bonding, van der waals interactions.
Explanation:the above listed are the interaction that that contribute
Hello,
To solve we need to know the formula for speed
The formula is D/T=S (Distance of time=speed)
Now all we have to do is plug in the numbers.
20/40= 1/2 or 0.5
SO the speed is 0.5 m/s
Have a great day!
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).