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poizon [28]
4 years ago
10

SOS i need help , I need a paragraph explaining what properties chave de burned paper

Physics
1 answer:
tensa zangetsu [6.8K]4 years ago
7 0
Ill answer if you give me the exact question cuz I want to give you a good format
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Kepler was able to mathematically model that what shape was the most likely orbital shape for objects around the sun?
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The answer is Elliptical orbit.

Hope this helps!

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4 years ago
Compared to the tropical rainforests, the temperate rainforests generally have __________.
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4 years ago
ASAP FIRST TO ANSWER CORRECTLY WILL BE BRAINLIEST
ioda

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1.Divergent

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3 years ago
Read 2 more answers
A Ferris wheel turns at a constant 150.0 revolutions per hour. (a) Express this rate of rotation in units of radians per second.
RUDIKE [14]

Answer:

(a) 0.261 rad/s

(b) 1007.72 m

Explanation:

The angular velocity of the Ferris wheel is 150.0 revolutions per hour.

(a) To calculate the angular velocity of the wheel in units of radians per second, you take into account the following equivalence:

1 hour = 3600 seconds

1 revolution = 2π radians

You use the previous conversion factors:

150.0\ \frac{rev}{h}*\frac{2\pi \ rad}{1\ rev}*\frac{1\ h}{3600\ s}=0.261\frac{rad}{s}

In units of radians per seconds the wheel turns at 0.261 rad/s

(b) To find the arc length described by the wheel, you first calculate the angle described by the  wheel in the time t, by using the following formula:

\theta=\omega t     (1)

ω: angular velocity = 0.261 rad/s

t: time = 4.95 min

You first convert the time to units of seconds

4.95min*\frac{60s}{1min}=297s

Next, you replace the values of the parameters in the equation (1):

\theta=(0.261\frac{rad}{s})(297s)=77.51rad

Next, you use the following formula for the arc length:

s=r\theta     (2)

r: radius of the wheel = 13.0 m

You replace the values of the parameters in the equation (2):

s=(13.0m)(77.51rad)=1007.72m

The arc length described by the wheel is 1007.72m

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4 years ago
Galileo was a contemporary of
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Brahe & Kepler

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