Question

Help me before 7:15

Answer 1

A. (2,6)(5,0)
     slope = (0 - 6) / (5 - 2) = -6/3 = -2

y = mx + b
slope(m) = -2
(2,6)..x = 2 and y = 6
sub and find b, the y int
6 = -2(2) + b
6 = -4 + b
6 + 4 = b
10 = b

so line A , equation is : y = -2x + 10
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B. (0,2)(6,6)
    slope = (6 - 2) / (6 - 0) = 4/6 which reduces to 2/3

y = mx + b
slope(m) = 2/3
(0,2)...x = 0 and y = 2
sub and find b, the y int
2 = 2/3(0) + b
2 = b

LIne B, equation is : y = 2/3x + 2
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so we have : 
y = 2/3x + 2
y = -2x + 10

2/3x + 2 = -2x + 10 ..multiply by 3
2x + 6 = -6x + 30
2x + 6x = 30 - 6
8x = 24
x = 24/8
x = 3

y = -2x + 10
y = -2(3) + 10
y = -6 + 10
y = 4

solution is (3,4).....3/4 is the solution to both lines <===

Answer 2

Answer:

3,4 for both lines

Step-by-step explanation: