The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
can you make the question clear so I can answer you the question.
The cost is $45.50 for the bag
Answer:
B
Step-by-step explanation:
That was actually trickier than I thought it would be
I was looking for 4(x-4), but 4(x-2)(x+2) also works
Mean is the average. You would add up all the numbers and divide by how many numbers you have. 433/10=43.3