All categories

3 years ago

How do you solve 8a squared plus 2 = 634

Mathematics

1 answer:

Inga [223]3 years ago

8 0

Answer:

a ≈ 8.9

Step-by-step explanation:

Set up the equation as so:

8a^2 + 2 = 634

First, subtract two from both sides:

8a^2 = 632

Then, divide by 8 to further isolate the variable.

a^2 = 79

To get rid of the squared, you have to take the square root of both sides. The square root of 79 is roughly 8.9. Ergo, a ≈ 8.9

You might be interested in

Given the equation

tatiyna

Answer:

A. Subtract x from both sides: (i.e. 5+x-12 = x-7 <--> 5-12 = -7)

This equation is identically true, so it holds no matter what x is.

B. This one is pretty self-explanatory

Step-by-step explanation:

u wrote the question wrongly the answer is in answer box

This question also my teacher gives me

hope it helps

8 0

3 years ago

A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei

oksano4ka [1.4K]

The answer is x=42.8+- (plus or minus) 12

So he should either have $30.80 or $44.80 left

6 0

3 years ago

What is the solution to the system of equations?

dusya [7]

Answer:

1.x=-4+ y/2 - z/2

2. X=-4-y-z

3. x=y/3-2/3

Step-by-step explanation:

8 0

3 years ago

X^-2+4x^-1+3=0 solve by making appropriate substitution

Alex

ANSWER

$x = - 1 \: or \: x = - \frac{1}{ 3}$

EXPLANATION

The given equation is:

${x}^{ - 2} + 4 {x}^{ - 1} + 3 = 0$

Recall that:

${a}^{ - m} = \frac{1}{ {a}^{m} }$

$\frac{1}{ {x}^{2} } + \frac{4}{x} + 3 = 0$

${( \frac{1}{x} )}^{2} + 4( \frac{1}{x} ) + 3 = 0$

Let

$u = \frac{1}{x}$

Our equation then becomes:

${u}^{2} + 4u + 3 = 0$

The factors of 3 that add up to 4 are:

${u}^{2} + 3u + u + 3$

$u(u + 3) + 1(u + 3) = 0$

$(u + 1)(u + 3) = 0$

$u + 1 = 0 \: or \: u + 3 = 0$

$u = - 1 \: or \: u = - 3$

This implies that:

$\frac{1}{x} = - 1 \: or \: \frac{1}{x} = - 3$

$x = - 1 \: or \: x = - \frac{1}{ 3}$

7 0

3 years ago

You are graphing rectangle ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:

vampirchik [111]

Answer:

The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).

We are to plot D on the graph.

Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.

Step-by-step explanation:

3 0

2 years ago