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yulyashka [42]
3 years ago
6

What is the solution of x=2+ sqrt x-2

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

The answer is option 3.

Step-by-step explanation:

Firstly, we have to move the unrelated term to the other side :

x = 2 +  \sqrt{x - 2}

x - 2 =  \sqrt{x - 2}

Then, you have to get rid of square root by squaring both sides :

{(x - 2)}^{2}  =  {( \sqrt{x - 2} )}^{2}

{x}^{2}  - 4x + 2 = x - 2

{x}^{2}  - 4x + 4 - x + 2 = 0

{x}^{2} - 5x + 6 = 0

Next, you have to solve it :

{x}^{2}  - 5x  + 6 = 0

{x}^{2}  - 2x - 3x + 6 = 0

x(x - 2) - 3(x - 2) = 0

(x - 2)(x - 3) = 0

x - 2 = 0 \\ x = 2

x - 3 = 0 \\ x = 3

wariber [46]3 years ago
4 0

Answer:

C

Step-by-step explanation:

x=2+\sqrt{x-2} \\\\x-2=\sqrt{x-2} \\\\(x-2)^2=\pm(x-2) \\\\x^2-4x+4=\pm(x-2) \\\\

x^2-5x+6=0 OR x^2+3x+2=0

x=2 and 3

Hope this helps!

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Answer:

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Step-by-step explanation:

It is given that,

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