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yulyashka [42]
3 years ago
6

What is the solution of x=2+ sqrt x-2

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

The answer is option 3.

Step-by-step explanation:

Firstly, we have to move the unrelated term to the other side :

x = 2 +  \sqrt{x - 2}

x - 2 =  \sqrt{x - 2}

Then, you have to get rid of square root by squaring both sides :

{(x - 2)}^{2}  =  {( \sqrt{x - 2} )}^{2}

{x}^{2}  - 4x + 2 = x - 2

{x}^{2}  - 4x + 4 - x + 2 = 0

{x}^{2} - 5x + 6 = 0

Next, you have to solve it :

{x}^{2}  - 5x  + 6 = 0

{x}^{2}  - 2x - 3x + 6 = 0

x(x - 2) - 3(x - 2) = 0

(x - 2)(x - 3) = 0

x - 2 = 0 \\ x = 2

x - 3 = 0 \\ x = 3

wariber [46]3 years ago
4 0

Answer:

C

Step-by-step explanation:

x=2+\sqrt{x-2} \\\\x-2=\sqrt{x-2} \\\\(x-2)^2=\pm(x-2) \\\\x^2-4x+4=\pm(x-2) \\\\

x^2-5x+6=0 OR x^2+3x+2=0

x=2 and 3

Hope this helps!

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Answer:

\displaystyle \overrightarrow{YZ} = \

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<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

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Point Z(3, -4)

<u>Step 2: Find</u>

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6 0
2 years ago
Which of the following ordered pairs are solutions to the system of equations below?
Genrish500 [490]

Answer:

x = 43/12

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4x + 4y = -9

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12x = 43

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4 0
3 years ago
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lara [203]

Answer:

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Step-by-step explanation:

x = -b +/- square root(b^2 - 4ac) / 2a

ax^2 + bx + c = 0

these are both the quadratic formula but one is solved for the x and another for 0

a= 1

b= 6

c = -13

x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)

x = -6 +/- sqrt( 36 + 52) / 2

x= -6 +/- sqrt (88) / 2

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8 0
2 years ago
Please HELP!!!!! I need to know the missing value. PLease!!!!!!!!!!!!!!
GuDViN [60]

Answer:

w = 21.4 ft

Step-by-step explanation:

Area of Trapezoid = Area = (a+b)/2 * h

Where a and b are the bases of trapezoid, and h is the height.

In the figure we are given:

a= 32.3 ft

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h= 22.9 ft

Area = 614.865 ft²

Putting values in formula

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614.865 = (32.3 + w) / 2 * 22.9

1229.73 = 32.3 + w * 22.9

1229.73 / 22.9 = 32.3 +w

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