Answer:
6 in
Step-by-step explanation:
Let x = the side length of the original square.
They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.
The area of the smaller square is (x - 3)².
The area of the original square is x²
I assume the area of the smaller square is ¼ that of the original square. Then
1. Solve for x
2. Calculate the side length of the smaller square
(a) x = 2
Side length = x - 3 = 2 - 3 = -1 in.
IMPOSSIBLE. You can't have a negative side length.
(b) x = 6
Side length of smaller square = 6 - 3 = 3 in.
Side length of original square = x = 6 in
Check:
OK.
37 1/2 this is the answer
Answer:
51.60% probability that a randomly selected adult has an IQ between 86 and 114.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the probability that a randomly selected adult has an IQ between 86 and 114.
Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So
X = 114
has a pvalue of 0.7580
X = 86
has a pvalue of 0.2420
0.7580 - 0.2420 = 0.5160
51.60% probability that a randomly selected adult has an IQ between 86 and 114.
Answer:
For 4 years the money was in the account .
Step-by-step explanation:
Formula
As given
Bonita deposited 1300 into a bank account that earned 5.75% simple interest each year.
She earned $299 in interest before closing the account.
Principle = $1300
Rate = 5.75%
Simple interest = $299
Putting all the values in the formula
Time = 4 years
Therefore for 4 years the money was in the account .
