As for the domain, the only restriction comes from the logarithm. The argument of a logarith must be strictly positive, so we have
![x-2>0 \iff x>2](https://tex.z-dn.net/?f=%20x-2%3E0%20%5Ciff%20x%3E2)
As for the range, we have:
- The range of
are all real numbers - If we change to
we're translating the function horizontally, so the range remains the same - If we change to
we're stretching the function horizontally, so the range doesn't change - If we change to
we're translating the function 1 unit up, but the range is already all the real numbers, so it doesn't change.
Answer:
These triangles cannot be proved congruent
Step-by-step explanation:
The theorems for congruence are SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.
Answer:
C
Step-by-step explanation:
The top part is 4.5 inches and teh bottom is 27 so it is 36
Answer:
100r^4 + 400r^3 + 600r^2 + 400r + 100
Step-by-step explanation:
Expanding ( r + 1 )^4 gives :-
r^4 + 4r^3 + 6r^2 + 4r + 1
So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-
100r^4 + 400r^3 + 600r^2 + 400r + 100
The answer would be 0 solutions.
Here, we see <em>|</em><em />x+6<em>|</em><em /> = 2.
Oh wow! A foreign object!
|x+6|... two lines... what is that?
That is called absolute value. Whatever is inside the two lines, must have a positive answer!
Let's pretend we have a machine that has this absolute value function activated.
What we put in, we must get a positive answer out.
Let's put in -6.
-6 ==> BEEP BEEP ==> 6
Let's try 3.
3 ==> BEEP BEEP ==>3
Whatever we put in, if it is negative or positive, what comes out is always positive.
So, for how many values <em>x</em> is |x+6|=-2 true?
None, because the answer <em>must</em><em /> be positive!
-2 is not positive, <em>2</em><em /> is.